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Wednesday, February 20, 2019

Making Salt Lab

Lets forge Salt Purpose Could NaCl be made using NaHCO3, hydrochloric acid, and a turn check mark? Hypothesis If I combined NaHCO3, hydrochloric acid, and a stewing chip I think it will form NaCl because when you balance the equation it makes a new chemical reaction. Materials needed evidence thermionic valve cleaner, outpouring vacuum supply, screen out subway system tongs, hot plate, a scale, graduated cylinder, water, goggles, fire retardant glove, beaker, test tube holder, a scoopula, hydrochloric acid, sodium bicarbonate, soap, pipette, and a boiling chip. Procedures 1.Clean your test tube with a test tube cleaner, soap, and water. Make sure the test tube is clean and dry. 2. Place a boiling chip in the test tube and stones throw it. 3. Add 1g of NaHCO3(sodium bicarbonate) to the test tube with the scoopula, then measure. 4. get under ones skin about 5mL of hydrochloric acid in your graduated cylinder. Using your pipette get the hydrochloric acid to the NaHCO3. It w ill start to bubble, when the bubbling stops, dont sum up anymore acid. 5. Once the bubbling stops, swirl whats inside the test tube to be sure everything mixes together. 6.Place the test tube in a beaker with water. It will start to boil. Continue letting it boil until all eloquent is evaporated out of the test tube. 7. Once the test tube cools off measure whats inside the test tube. 8. Place the test tube natural covering inside the beaker on the hot plate for 2-3 minutes. 9. Allow the test tube to cool and re-weigh it again. Observation/Data NaHCO3+HClNaCl+H2O+CO2 1gNaHCO3*1molNaHCO3/84gNaHCO3*1molNaCl/1molNaHCO3*58gNaHCO3/1molNaCl=. 6904761905 . 6904761905theoretical come back 1actual yield 1/. 6904761905=1. 448275862 1. 448275862*100=144. 275862 144. 8275862percent yield atomic reactor of test tube & boiling chip 20g Mass of test tube, boiling chip & NaHCO3 21g Mass of NaHCO3(b-a) 1g Mass of test tube & boiling chip NaCl (1st hearing) 20g Mass of test tube & boiling chip N aCl (2nd hearing) 21g Mass of NaCl (e-a) 1g Conclusion My hypothesis was correct because two substances together formed NaCl in the end. In the lab everything worked out adept because in the end none of my masses were the same as I started with. It weighed 20g in the beginning and ended with 21g and the mass of NaCl 1g.

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